1/2Kx^2
Rewrite the equation as 1 2 kx2 U 1 2 k x 2 U. Youll get a detailed solution from a subject.
The Dimensions Of K In The Equation W 1 2kx 2 Is
Multiply both sides of the equation by 2 2.
. Solve for x E12kx2. Arent d and x the same. If we had instead defined the force as F -2kx then U would be kx².
1 2 kx2 U 1 2 k x 2 U. Solve for x U12kx2. Comments sorted by Best Top New Controversial QA Add a Comment.
Thus you can divide by k and move the constant term to RHS obtaining xx k2 1. Indeed f x 2x is non-negative for x 0. Derivative ddx12 k x2 k k2 x.
This force leads to the potential energy U 12 kx². U 1 2 kx2 U 1 2 k x 2. E 1 2 kx2 E 1 2 k x 2.
1 2 kx2 E 1 2 k x 2 E. What is the difference between the equations Fkx F-kx and F12kx2 in spring problem situations. The dimensions of K in the equation W12Kx2 is.
But the work done in stretching a spring 12 kx2 isnt work Fd. Both 12Fx and 12 kx2 are correct and equivalent to each other. Where E is energy J and x is distance cm.
Multiply both sides of the equation by 2 2. Potential energy 12spring constant distance from equilibrium2. So using WFd and F-kx hookes law shouldnt the work come out to.
The slight preference for 12 kx2 is down simply to the fact that you need only measure one variable- the dispalcement x. Hookes law gives us the force we need to find elastic potential energy. Integral k2 x22 dx k2 x36.
Prev Question Next Question. 12 k x2 k. Determine the fundamental dimensions for k in the equation below.
X 2 14142 k 0. Solve for x k12 kx2 Mathway Trigonometry Examples Popular Problems Trigonometry Solve for x k12 kx2 k 1 2 kx2 k 1 2 k x 2 Rewrite the equation as 1 2 kx2 k 1. The potential energy can be found using the formula.
The spring constant is the measure of stiffness of a spring. Alternatively you can assume that the spring in equilibrium has a. First thing we can find out is that k 0.
Like all work and energy the unit of potential energy is the Joule J where 1 J 1Nm 1 kg m2s2. Looking at a graph of force versus. U 12kx2 U 12 750 Nm 040 m 2 U 060 Nm U 060 J The elastic potential energy stored by the spring when it is has been.
This problem has been solved. The dimensions of K in the equation W 12 Kx2 is. Asked Sep 2 2021 in Physics by Vaibhav02 380k points.
Although both are rigorous my schools chemistry is a. Im in both chem and physics 1 right now. Rewrite the equation as 1 2 kx2 E 1 2 k x 2 E.
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